Question: You Have Been Examining For Variants Of A Bacterial Pathogen (Clostridium Difficile) And You Think You Have Found One. The Wild Type Bacteria Has A Section Of DNA With The Sequence Below (non-template Strand Shown). This Section Encodes A Small But Important Peptide. The Sequence Of The Variant Is Below The Wild Type. Based On This, Determine Where ...

Question: You Have Been Examining For Variants Of A Bacterial Pathogen (Clostridium Difficile) And You Think You Have Found One. The Wild Type Bacteria Has A Section Of DNA With The Sequence Below (non-template Strand Shown). This Section Encodes A Small But Important Peptide. The Sequence Of The Variant Is Below The Wild Type. Based On This, Determine Where …

You have been examining for variants of a bacterialpathogen (Clostridium difficile) and you think you havefound one. The Wild type bacteria has a section of DNA with thesequence below (non-template strand shown). This section encodes asmall but important peptide. The sequence of the variant is belowthe wild type. Based on this, determine where the difference is,what type of mutation it is, and what effect this mutation mighthave on the gene product and the resultant phenotype of the variantpathogen. (NOTE THE START AND STOP CODONS!)

5′ ATGAAACAGGCCATCTAG 3′ WildType

5’ATGAAATAGGCCATCTAG 3′ Variant

Question: Replicatloh Tork. Direction Of New Synthesis Newly Synthesized Strand DNA Polymerase II Waar RNA Primer DNA Helicase DNA Gyrase Leading Strand Template Acow Tau Parental DNA RNA Primer DNA Polymerase III DNA Primase Newly Synthesized Strand Lagging Strand Template Single-strand DNA-binding Proteins Direction Of New Synthesis
Question: Direction Of Now Synthesis Newly Synthesized Strand DNA Polymeraselt And Something Is Wrong With Replisome Shown In This Cartoon – What Do You Think It Is? Can You Spot The Problem? ANA Primer Loading Strand Template ONA Beland DRAG Corsa Tau Parental ONA RNA Primer DNA Polymeraselt DNA Prime Newly Synthesized Strand Lagiging Strand Template Singlo-strand …
Question: The Following Sequence Contains A Mismatch Due To A Mistake By DNA Polymerase While It Was Replicating The Template Strand. Template Strand: 5’ AGCCTAGTGCTAATC 3’ Newly Replicated Strand: 3’ TCGGATCACGCTTAG 5’ Which Of The Following Statements Is FALSE? A. In Bacteria, Mismatch Repair Uses Methylation Of The Template Strand To Determine Which …
Question: Drawing Sequencing 1. Draw 2 Lines To Represent Double-stranded DNA; Indicate The 5′ & 3′ Ends Of Each Strand. 2. Separate The Strands (using Heat). 3. Choose One Strand To Be The Template Strand & Anneal A Short Primer To It; Indicate The 5′ & 3′ Ends Of Both The Primer & The Template Strand. 4. Draw The First 5 Possible Terminations Of The Sequencing …
Question: 2 A) The Following Nucleotide Sequence Is Found On The Template Strand Of DNA: 3′ – TAC TGG CCG TTA GTT GAT ATA ACT-5′ Determine The Amino Acids Of The Encoded Peptide, Then Provide The Altered Amino Acid Sequence Of Protein That Would Result From Each Of The Following Mutations And Provide Their Classification (eg, Missense, Nonsense, Etc). (4.5 Marks) …
Question: What Is The Function Of UvrA? O It Detects Distortions In The DNA Helix It Melts The DNA Strand. It Removes A Patch Of Nucleotides From One Of The Strands. It Identifies The Parental Strand. Question 26 0.7 Pts You Are A Scientist Given Two Samples Of DNA. One Sample Contains DNA Which Has Been Replicated, But ONLY Leading Strands. The Other Sample …
Question: TIS.IT In The Following Data Presented By Lu Et. Al., Which Conclusion Is Best Supported By The Data Shown? Concentration Of TraJ (M) (C) 0 0.1 0.2 0.3 0.5 0.781 1.5 2 3 4 6 TraJ/ArcA DNA Complexes ArcADNA Free DNA Select One: O A. Only Tra) Can Bind DNA B. Only Aroa Can Bind DNA C. Tra) Binds DNA Only After ArcA First Binds The DNA O D. ArcA Binds …
Question: Question 14 What Type Of Mutation Happened To Sequence One For It To Become Sequence Two? Translate Both Sequences Using The Codon Chart. Explain The Differences. Be Sure To Count In Sets Of 3, Remember The Difference Between DNA & RNA. AUG CCA GGG GCAUCA AAA UAA Sequence One: Coding – Sequence Two: Coding – AUG CCA GGG GCA UGA AAA VAA Gyor GU А с …
Question: The Bacterium Bacillus Aggie Reproduces By Binary Fission. If A Culture Is Inoculated With 1×103 Bacteria, How Many Bacteria Will Be Present After 10 Generations? 1.0 X 104 Bacteria 1.0 X 105 Bacteria ОО 1.0 X 106 Bacteria Which Of The Following Pieces Of Information Must You Have To Determine The Number Of Cells/ml In A Bacterial Culture Using A …
Question: 6. Which Of The Following MRNA Sequences Corresponds To The DNA Sequence Below: GAGTACCCT A. GAGUACCCU B. CICATGGGA C. CUCAUGGGA D. ICCCATGAG 7. …………… Using The Box Below, Determine The Correct Sequence Of Aming Acids From The Following Strand Of MRNA 5′ U CGCGA CCCC GA GCU 3′ A. Serine, Arginine, Proline, Arginine, Alanine B. Serine, Serine, …

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